Question

How do you solve `3y²+14y=5`?

Answer 1

`1/3 and -5`

Explanation:

`f(y) = 3y^2 + 14y = 5 = 0.`
Use the new Transforming Method (Google, Yahoo Search).
Transformed equation: `f'(y) = y^2 + 14y - 15.`
Since a + b + c = 0, the 2 real roots of f'(y) are: ( 1) and `(c/a = - 15)`.
Therefor, the 2 real roots of f(y) are: `(1/3) and (-15/3 = - 5)`
Answers: `1/3` and -5