Question

How do you evaluate `log_10 200 - log_10 2`?

Answer 1

`2`

Explanation:

From the laws of logs we have that

`log_ax-log_ay=log_a(x/y)`

So in this particular case we get that

`log_10 200-log_10 2 = log_10 (200/2)`

`=log_10 100`

`=2`. (since `10^2=100`)