Question

How do you find `abs(2 - 6i)`?

Answer 1

`|2-6i|=sqrt40`

Explanation:

Let `z=x+iy` be any complex number in rectangular form.

Then its modulus is given by `|z|=sqrt(x^2+y^2)`

So in this particular case we get

`|2-6i|=sqrt(2^2+(-6)^2)=sqrt40`.