How do you find the inverse of $ln (x^{2})$ $ln(x^2)$ and is it a function?

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Answer 1 · 2016-03-28T07:26:11

If $y = ln (x^{2})$ $y = ln(x^2)$ , then

$e^{y} = x^{2}$ $e^y = x^2$

$x = \pm \sqrt{e^{y}}$ $x = +- sqrt{e^y}$

It is not a function, as given a value for $y$ $y$ , there can be sometimes 2 values of $x$ $x$ (due to the plus-minus sign).

How do you find the inverse of ln(x2)ln(x^2) and is it a function?