Question

It takes 23.5 kJ of heat energy to raise the temperature of 100 g of a substance by 50°C. What is the substance?

Answer 1

Most probably liquid ammonia.

Explanation:

Heat energy `W=mcDeltaT`

`therefore c=W/(mDeltaT)`

`=(23500J)/(0.1kgxx50 K)`

`=4700J//kg.K`.

Consultation of a standard data sheet for specific heat capacities reveals that this substance is most probably `NH_(3(l))`.