Question

How do you solve `9^(2y) = 66`?

Answer 1

`y=(1/2)(log 66/log 9)` =0.9534, nearly.

Explanation:

Equating logarithms, `log(9^(2y))=log 66`.
So, 2y log 66 = log 9, using `log(a^m)=mlog a`..
`y=(1/2)(log 66/log 9)`