How do you solve #(x-2)/2-(x+2)/4=(1/2)#?

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Answer 1 · 2016-03-28T19:34:35

#x=8#

Write as#" " (2(x-2))/4-(x+2)/4=2/4#

Multiply everything by 4 giving:

#2(x-2)-(x+2)=2#

#2x-4-x-2=2#

#x-6=2#

Add 6 to both sides

#x=8#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~
Check
#(8-2)/2-(8+2)/4=?#

#6/2 -5/2=?#

Left hand side = right hand side# = 1/2" "#confirmed!