Question

How do you simplify `(18b^2c) / (4bc^3 ) times (3ab)^-2 / (5a^2c^3)`?

Answer 1

`(18b^2c)/(4bc^3)xx((3ab)^-2)/(5a^2b^3)=(18b^2c)/(4bc^3)xx(1)/((3ab)^2xx5a^2b^3)`
`=(18b^2c)/(4bc^3)xx(1)/(9a^2b^2xx5a^2b^3)`
`=(18b^2c)/(4bc^3)xx(1)/(45a^4b^5)`
`=(18b^2c)/(180a^4b^6c^3)`
`=1/(10a^4b^4c^2)`