Question

How do you solve `7 (2^x) = 5^(x-2)`?

Answer 1

x = `log 175/log 2.5`

Explanation:

`5^(x-2) = 5^x5^(-2)= 5^x/5^2=5^x/25`.
So, `5^x/2^x=175`.
`(5/2)^x.= 175`.
`x log 2.5 = log 175`
`x=log 175 /log 2.5`