Question

How do you factor the trinomial `2x^2 + 4x - 198`?

Answer 1

y = 2(x - 9)(x + 11)

Explanation:

`y = 2(x^2 + 2x - 99)`
Find 2 numbers knowing sum (b = 2) and product (c = -99).
Factor pairs of (-99) --> (-9, 11). This sum is 2 = b. Then these 2 numbers are -9 and 11.
`y = 2(x - 9)(x + 11)`