How do you find the asymptotes for #h(x)=(x^2-4) / x#?
1 Answer
Mar 30, 2016
vertical asymptote x = 0
oblique asymptote y=x
Explanation:
Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation , set the denominator to zero.
hence : x = 0 is the asymptote
Horizontal asymptotes occur when the degree of the numerator is ≤ to the degree of the denominator. This is not so here , hence there are no horizontal asymptotes.
Oblique asymptotes occur when the degree of the numerator > than the degree of the denominator. This is the case here.
divide numerator by x
# ((x^2)/x - 4/x) = x - 4/x # As
# x tooo , 4/x to 0 " and " y to x #
#rArr y = x " is the asymptote " # Here is the graph of the function.
graph{(x^2-4)/x [-10, 10, -5, 5]}