How do you find $abs( -3+4i)$ ?

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Answer 1 · 2016-03-30T13:30:51

$|-3+4i|=sqrt((-3)^2+4^2)=5$

Let $z=x+iy$ be any complex number in rectangular form.

Then its modulus is given by $|z|=sqrt(x^2+y^2)$ .

So in this case we get

$|-3+4i|=sqrt((-3)^2+4^2)=sqrt25=5$

How do you find abs( -3+4i)abs( -3+4i)?