Question

How do you solve `( x - 4)^2 = 12`?

Answer 1

`x=7.464`
`x=0.536`

Explanation:

Given -

`(x-4)^2=12`
`x^2-8x+16=12`
`x^2-8x+16-12=0`
`x^2-8x+4=0`
`x=(-b+-sqrt(b^2-(4ac)))/(2a)`
`x=(8+-sqrt((-8)^2-(4 xx1 xx4)))/(2 xx 1)`
`x=(8+-sqrt(64-16))/2`
`x=(8+-sqrt(48))/2`
`x=(8+-6.928)/2`
`x=(8+6.928)/2=14.928/2=7.464`
`x=7.464`
`x=(8-6.928)/2=1.072/2=0.536`
`x=0.536`