The gas inside of a container exerts 12 Pa of pressure and is at a temperature of 250 ^o C. If the temperature of the gas changes to 80 ^oK with no change in the container's volume, what is the new pressure of the gas?

1 Answer
Mar 31, 2016

1.836Pa (4s.f.)

Explanation:

First convert temperature to Kelvin, 250+273=523K

Ideal gas law: P_1V_1=nRT_1
Calculate for number of moles:
n=(P_1V_1)/(RT_1)=(12V_1)/(8.314*523)=2.760times10^-3V_1

Use Ideal gas law again:
P_2V_2=nRT_2
Since V_2=V_1:
P_2V_1=2.760times10^-3V_1*8.314*80
V_1s cancel to leave:
P_2=2.760times10^-3*8.314*80=1.836Pa