How do you factor #5a^3-a^2-5a+1#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 2 Answers Binayaka C. Apr 2, 2016 #(5a-1)(a+1)(a-1)# Explanation: #5a^3-a^2-5a+1 = 5a^3-5a^2+4a^2-4a-a+1=5a^2(a-1)+4a(a-1)-1(a-1) =(5a^2+4a-1)(a-1)= (5a^2+5a-a-1)(a-1)={5a(a+1)-1(a+1)}(a-1) =(5a-1)(a+1)(a-1)#[Ans] Answer link P dilip_k Apr 2, 2016 #=5a(a^2-1)-1(a^2-1)# #=(a^2-1)(5a-1)=(a+1)(a-1)(5a-1)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1507 views around the world You can reuse this answer Creative Commons License