Question

How many grams of `CO_2` are produced from 125 g of `O_2` and excess `CH_4` in the equation `CH_4 +2O_2-> CO_2 + 2H_2O`?

Answer 1

Here `CH_4` being excess `O_2` will be consumed fully.

We know from above equation
2 mole or 64 g `O_2` produces 1 mole or 44 g `CO_2`
So 125 g `O_2` will produce `44/64xx125=85.9 g CO_2`