How much work would it take to push a 6 kg weight up a 12 m plane that is at an incline of pi / 4 ?

1 Answer
Apr 2, 2016

51 Joules

Explanation:

Here,
Hypotenuse (h) = 12m
Angle of inclination (theta)= π/4
Perpendicular (p) = ?

We have, Sin theta = p/h
or, Sin (π/4) = p/12
or, p = 12/sqrt(2)
Hence, p = 8.5 m, which is the distance travelled.

Since work(W) is given by
W = F * S,
Where F = Force ( here weight) = 6 kg wt = 6 N
(Note kg wt, unlike kg, is same as Newton and is a unit of weight, not mass).
S is the distance traveled given by the perpendicular 8.5m
Therefore,
W = 6 * 8.5 = 51 "Joules"