Question

How do you solve `x^2 + 3 = –4x` using the quadratic formula?

Answer 1

First you put everything to one side, by adding `4x`

Explanation:

`->x^2+4x+3=0`

Quadratic formula: `x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)`

Or:
`x_(1,2)=(-4+-sqrt(4^2-4*1*3))/(2*1)`

`x_(1,2)=(-4+-2)/2->x_1=-1,x_2=-3`

Extra:
Factoring would have been easier here:
`(x+1)(x+3)=0`, with the same result.