How do you write the equation of the line with slope m = 3 and including point (3, 5)?

2 Answers
Apr 6, 2016

The equation of a line is

#y = mx + c#

and #m# is already given as #3#.

Therefore,

#y = 3x + c#

where #c# is found by substituting a point, which is given as #(3,5)#.

If #x = 3# and #y = 5# (as it says in the point given), then

#5 = 3*3 + c#
#5 = 9 + c#
#c = -4#

which we can substitute back in to give

#y = 3x - 4#

Apr 6, 2016

y = 3x - 4

Explanation:

One form of the equation of a line is : y - b = m(x - a )

where m represents the gradient (slope ) and (a,b) a point on the line.

here m = 3 and (a,b) = (3,5)

substituting these values into the equation.

y - 5 = 3(x - 3) → y - 5 = 3x - 9 → y = 3x - 4