How do you write the slope-intercept form of the equation parallel to y = 7x + 2, which passes through the point (1, -3)?

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Answer 1 · 2016-04-06T16:24:29

# y=7x-10#

Consider :#" " y=7x+c#............(1)

For the point #(x,y)->(1-3) #

Equation (1) becomes

#-3=7(1)+c#

Subtract 7 from both sides

#-10=c#

So equation (1) #-> y=7x-10#