What is the polar form of #( 19,55 )#?

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Answer 1 · 2016-04-06T19:29:52

Cartesian form: #(x,y)=(19,55)#
Polar form:#(r,theta)= (58.2,71^@)#

#r=sqrt(x^2+y^2)#

#theta = arctan(y/x)#

Answer 2 · 2016-04-06T19:37:24

≈ (58.19 ,1.238 )

To convert from Cartesian to Polar coordinates , use the formulae which links them.

#• r = sqrt(x^2 + y^2) #

#• theta = tan^-1(y/x)#

here x = 19 and y = 55

#rArr r = sqrt(19^2 + 55^2) = sqrt3386 ≈ 58.19 #

and # theta = tan^-1(55/19) ≈ 1.238" rad " (70.94^@) #