How do you solve 2x^2 -3x= -10 using the quadratic formula?

1 Answer
Apr 7, 2016

x=(3+- sqrt71i)/4

Explanation:

2x^2-3x=-10
=>2x^2-3x+10=0
a=2, b=-3 and c=10
Quadratic formula is
x=(-b+-sqrt(b^2-4ac))/(2a)
Putting values of 'a', 'b' and 'c' in above formula
x=(-(-3)+-(sqrt((-3)^2-4(2)(10))))/(2(2))
x=(3+-sqrt(9-80))/4
x=(3+-sqrt(-71))/4

x=(3+- sqrt71i)/4