How do you find the inverse of #f(x)=(x+2)/(x-1)# and is it a function?

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Answer 1 · 2016-04-07T13:42:03

#f^-1(x)=(x+2)/(x-1)#

#f(x)=(x+2)/(x-1)#

#y=(x+2)/(x-1)#

#y*x-y=x+2#

#y*x-x=y+2#

#x(y-1)=(y+2)#

#x=(y+2)/(y-1)#

#"change x and y vice versa"#

#y=(x+2)/(x-1)#

#f^-1(x)=(x+2)/(x-1)#

#"or simply:"#

#f(x)=(a x+b)/(c x+d)#

#f^-1 (x)=(-d x+b)/(c x+a)#