A container with a volume of #7 L# contains a gas with a temperature of #420^o C#. If the temperature of the gas changes to #540 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-04-07T13:48:02

#V_2=5,45 L#

#V_1=7L#
#T_1=420^o C" "420+273=693 ^o K#
#T_2=540^o K#
#V_2=?#

#V_1/T_1=V_2/T_2#

#7/693=V_2/540#

#7*540=V_2*693#

#3780=V_2*693#

#V_2=3780/693#

#V_2=5,45 L#