How do you solve #(x^2 - 7)/(x - 4) = 0#?

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Answer 1 · 2016-04-08T05:04:43

#x=sqrt7#

#color(blue)((x^2-7)/(x-4)=0#

Multiply both sides by #x-4#

#rarr(x^2-7)/cancel(x-4)*cancel(x-4)=0*x-4#

#rarrx^2-7=0#

Add #7# both sides

#rarrx^2-7+7=0+7#

#rarrx^2=7#

Take the square root of both sides

#rarrsqrt(x^2)=sqrt7#

#color(green)(rArrx=sqrt7#