Question

How do you simplify `(2y^-9h^2)(2y^0h^-4)^-6`?

Answer 1

`(1/32)(h^26/y^9)`

Explanation:

`(a^m)^n=a^(mn) and(abc)^n=a^nb^nc^n`
The second factor is `(2X.1.Xh^(-4))^(-6)=2^(-6)1^(-6)h^((-4)(-6))=2^(-6)h^24`.
`a^ma^n=a^(m+n)`.
The given expression simplifies to `2^(1-6)y^(-9)h^(2+24)=(1/32)(h^26/y^9)`.