How do you solve #1/3(9x-2) = 1/2(8x-6)#?
2 Answers
#x=7/3#
Explanation:
#color(blue)(1/3(9x-2)=1/2(8x-6)#
Use distributive property
#color(brown)(a(b+c)=ab+ac#
Remove the brackets and solve
Subtract
Add
Explanation:
#1/3(9x-2)=1/2(8x-6)#
#1/3(9x-2)=1/2*2(4x-3)#
#1/3(9x-2)=(4x-3)#
#color(red)3[1/3(9x-2)]=color(red)3(4x-3)#
#9x-2=3(4x-3)#
#9x-2=12x-9#
#3x=7#
#color(green)(|bar(ul(color(white)(a/a)x=7/3color(white)(a/a)|)))#