How do you write the equation of the circle where the point (-6,-5) lies on a circle whose center is at (-4,5)?

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Answer 1 · 2016-04-11T19:49:40

#color(red)((x+4)^2+(y-5)^2=104)#

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#r=sqrt(bar (A O)^2+bar(A B)^2)#
#r=sqrt((-6+4)^2+(-5-5)^2)#

#r=sqrt((-2)^2+(-10)^2)#

#r=sqrt(4+100)#

#r=sqrt104#

#r^2=104#

#O=(a,b)" circle's center"#
#O=(-4,5)#
#(x-a)^2+(y-b)^2=r^2" circle equation"#

#color(red)((x+4)^2+(y-5)^2=104)#