Question

How do you simplify and find the excluded value of `(3) / (x+1) + (5) / ( x - 1)`?

Answer 1

First we say that `x!=-1andx!=+1` or one of the denominators would be `=0` and that's not allowed.

Explanation:

Then we find a common denominator by multiplying:
`=3/(x+1)xx(x-1)/(x-1)+5/(x-1)xx(x+1)/(x+1)`

`=(3(x-1))/((x-1)(x+1))+(5(x+1))/((x-1)(x+1))`

`=(3x-3+5x+5)/(x^2-1)=(8x+2)/(x^2-1)`

And there is still the same restriction of `x!= +-1`