Question

How do you solve `Cos^2(x)-sin2(x)=sin^2(x)`?

Answer 1

`x = (npi)/2+pi/8`, n = 0, 1, 2, ...

Explanation:

Rearranging,

`sin (2x)=cos^2x-sin^2x=cos (2x)`

So, tan (2x) = 1
The principal solution is `2x = pi/4`.

The general solution is `2x=npi+pi/4`.

`x=(npi)/2+pi/8`, n = 0, 1, 2, 3, .....