What is the equation of the line between $(5,-6)$ and $(2,-2)$ ?

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Answer 1 · 2016-04-13T17:44:28

$y = -4/3x +2/3$

The formula for the slope of a line based upon two coordinate points is

$m = (y_2-y_1)/(x_2-x_1)$

For the coordinate points $(5,-6) and (2,-2)$
$x_1 = 5$
$x_2 = 2$
$y_1 = -6$
$y_2 = -2$

$m = (-2-(-6))/(2-5)$

$m = 4/-3$

The slope is $m = -4/3$

The point slope formula would be written as
$y - y_1 = m( x - x_1)$

$m = -4/3$
$x_1 = 2$
$y_1=-2$

$y - (-2) = -4/3 (x -2)$

$y + 2 = -4/3x +8/3$

$y cancel(+ 2) cancel(- 2)= -4/3x +2(2)/3 -2$

$y = -4/3x +2/3$

What is the equation of the line between (5,-6)(5,-6) and (2,-2)(2,-2)?