If #x^a+x^b = x^c# then what is #c# in terms of #a# and #b#?

1 Answer
Apr 14, 2016

There is no expression for #c# in terms of just #a# and #b#.
Its value would depend on #x# too.

Explanation:

I think this question is inspired by the identities:

#x^a * x^b = x^(a+b)#

#(x^a)^b = x^(ab)#

However, when we get to:

#x^a+x^b = x^c#

there is no simple expression for #c# in terms of #a# and #b#. It will depend on the value of #x# too.

Taking logs of both sides we get:

#log(x^a+x^b) = log(x^c) = c log(x)#

So:

#c = log(x^a+x^b)/log(x) = log_x(x^a+x^b)#

A particular concrete example would be:

#2^1 + 2^1 = 4 = 2^2#

#4^1 + 4^1 = 8 = 4^(3/2)#