If #x^a+x^b = x^c# then what is #c# in terms of #a# and #b#?
1 Answer
Apr 14, 2016
There is no expression for
Its value would depend on
Explanation:
I think this question is inspired by the identities:
#x^a * x^b = x^(a+b)#
#(x^a)^b = x^(ab)#
However, when we get to:
#x^a+x^b = x^c#
there is no simple expression for
Taking logs of both sides we get:
#log(x^a+x^b) = log(x^c) = c log(x)#
So:
#c = log(x^a+x^b)/log(x) = log_x(x^a+x^b)#
A particular concrete example would be:
#2^1 + 2^1 = 4 = 2^2#
#4^1 + 4^1 = 8 = 4^(3/2)#