How do you calculate #log_2 8^2 #? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Shwetank Mauria Apr 14, 2016 #log_2(8^2)=6# Explanation: #log_2(8^2)# can be written as #log_2((2^3)^2)# = #log_2(2^6)=6log_2(2)=6*1=6# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 1548 views around the world You can reuse this answer Creative Commons License