Question

How do you solve using the completing the square method `x^2 - 18x = 19`?

Answer 1

`x={-1,19}`

Explanation:

`x^2-18x=19`

`x^2-18x-19=0`

`(x-19)(x+1)=0`

`if (x-19)=0" ; "x=19`

`if (x+1)=0" ; "x=-1`

`x={-1,19}`