Question

If the length of a `15 cm` spring increases to `28 cm` when a `2 kg` weight is hanging from it, what is the spring's constant?

Answer 1

`k=150,92" N/m"`

Explanation:

`m=2kg`
`g=9,81 N/(kg)`

`G=m*g=2*9,81=19,62 N" Force acting to spring"`
`k:"spring constant"`
`Delta x=28-15=13 cm=0,13 m`
`F=G=k*Delta x`

`19,62=k*0,13`

`k=(19,62)/(0,13)`

`k=150,92" N/m"`