How do you solve #4^x * 3^(2x) = 6 #? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer P dilip_k Apr 16, 2016 #: . x=1/2# Explanation: #=>(4xx3^2)^x=6=36^(1/2)# #=>(36)^x=36^(1/2)# #: . x=1/2# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 7078 views around the world You can reuse this answer Creative Commons License