How do you convert $r^{2} = cos (θ)$ $r^2=cos(theta)$ to polar form?

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Answer 1 · 2016-04-16T11:49:14

It is in polar form. If you meant converting to rectangular form, that would be ${(x^{2} + y^{2})}^{\frac{3}{2}} = x$ $(x^2+y^2)^{3/2}=x$ .

Multiply by $r$ $r$ to get

$r^{3} = r cos (θ)$ $r^3=r\cos(\theta)$ .

Then put in $r = {(x^{2} + y^{2})}^{\frac{1}{2}}$ $r=(x^2+y^2)^{1/2}$ , $r cos (θ) = x$ $r\cos(\theta)=x$ .

How do you convert r^2=cos(theta)r2=cos(θ)r^2=cos(theta) to polar form?