Circle A has a radius of #4 # and a center of #(8 ,5 )#. Circle B has a radius of #3 # and a center of #(6 ,7 )#. If circle B is translated by #<3 ,1 >#, does it overlap circle A? If not, what is the minimum distance between points on both circles?
1 Answer
circles overlap
Explanation:
To determine wether the circles overlap or not , requires calculating the distance (d) between the centres and comparing this with the sum of the radii.
• If sum of radii > d , then circles overlap.
• If sum of radii < d , then no overlap.
Under a translation of
#((3),(1))# centre of B(6 , 7) → (6 + 3 , 7 + 1) → (9 , 8)
To calculate the distance (d) between centres use the
#color(blue)" distance formula "#
#color(red)(|bar(ul(color(white)(a/a)color(black)( d = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2))color(white)(a/a)|)))#
where# (x_1,y_1)" and " (x_2,y_2)" are 2 coordinate points " # let
# (x_1,y_1)=(8,5)" and " (x_2,y_2)=(9,8)#
#rArr d =sqrt((9-8)^2+(8-5)^2)=sqrt(1+9)=sqrt10 ≈ 3.16# now radius of A + radius of B = 4 + 3 = 7
Since sum of radii > d , then circles overlap.