How do you solve #log_3 3+log_3x=5#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer reudhreghs Apr 16, 2016 #x=81# Explanation: You can see straightaway that #log_3 3 = 1#, because #3^1=3#, so #1+log_3 x=5# #log_3 x=4# Raise both sides by #3#, #3^(log_3 x)=3^4# #x=3^4# #x=81# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1064 views around the world You can reuse this answer Creative Commons License