How do you verify #csc2(theta)=csc(theta)/(2cos(theta))#?

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Answer 1 · 2016-04-16T23:13:10

See below

LHS =left hand side, RHS =right hand side

LHS #=1/(sin (2 theta)) #

#=1/(2sinthetacostheta)#

#=1/(2costheta) * 1/sin theta#

#=1/(2costheta) csc theta #

#=csc theta/(2cos theta) #

#=RHS#