Question #9695c

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Answer 1 · 2016-04-17T01:16:26

See below

#cos theta/(1-sin theta) + cos theta/ (1+sin theta) = 4#

#(cos theta (1+sin theta)+cos theta(1-sin theta))/((1-sin theta)(1+sin theta)) =4#

#(cos theta + sin theta cos theta+ cos theta-sin theta cos theta)/(1-sin^2 theta)=4#

#(2cos theta)/cos^2 theta = 4#

#2/cos theta =4#

#2=4cos theta#

#1/2 = cos theta#

#theta = cos^-1 (1/2)#

#theta=+- 60 + 360^@n#