How do you convert $x^{2} = 4 y$ $x^2=4y$ into polar form?

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How do you convert $x^{2} = 4 y$ $x^2=4y$ into polar form?

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Answer 1 · 2016-04-17T02:07:32

Putting $x = r cos θ and y = r sin θ$ $x =rcostheta and y =rsintheta$
$r^{2} {cos}^{2} θ = 4 r sin θ \Rightarrow r = 4 tan θ sec θ$ $r^2cos^2theta=4rsintheta=>r=4tantheta sectheta$

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How do you convert $x^{2} = 4 y$ $x^2=4y$ into polar form?

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