Question

How do you solve `3n^2-14n=-16`?

Answer 1

2 and `8/3`

Explanation:

`y = 3n^2 - 14n + 16 = 0`
Use the new Transforming Method (Google, Yahoo Search)
Transformed equation `y' = n^2 - 14n +48 = 0`
Factor pairs of (ac = 48) --> ...(4, 12)(6, 8). This sum is 14 = - b.
Then, the 2 real roots of y' are: 6 and 8.
Back to y, the 2 real roots are: `6/3 = 2` and `8/3`