How do you solve 2x^2 - 32 = 02x232=0?

1 Answer
Apr 17, 2016

x = 4, -4x=4,4

Explanation:

You can factor out a 2 as the GCF.

2(x^2 - 16) = 02(x216)=0

x^2 - 16x216 is the difference of perfect squares, which are (x-4)(x+4)(x4)(x+4)

Therefore, you now have 2(x-4)(x+4)2(x4)(x+4).

To solve this quadratic means to find the roots of it (the points where the parabola will cross the x-axis).
x - 4 =0x4=0
x = 4x=4

and

x + 4 = 0x+4=0
x = -4x=4

Therefore, x = -4, 4