Question

The gas inside of a container exerts `12 Pa` of pressure and is at a temperature of `320 ^o K`. If the pressure in the container changes to `64 Pa` with no change in the container's volume, what is the new temperature of the gas?

Answer 1

`T_2=1706,67 ^o K`

Explanation:

`P_1/T_1=P_2/T_2`

`P_1=12Pa`
`T_1=320 ^o K`

`P_2=64 Pa`
`T_2=?`

`12/320=64/T_2`

`T_2=(320*64)/12`

`T_2=1706,67 ^o K`