Question

How many solutions are there for the equation `x^2 + 16 = 8x`?

Answer 1

! solution only. Which is `x=4`

Explanation:

Subtract `8x` from both sides

`x^2-8x+16=0`

Note that `(-4)xx(-4) = +16" and "(-4)+(-4)=-8`

So we have:

`(x-4)(x-4)=0" "->" "(x-4)^2=0`

The only solution is `x=(+4)`