Question

How do you solve for x in `y=(0.8)(0.84)^x`?

Answer 1

`x=(ln(y/0.8))/ln(0.84)`

Explanation:

`y/0.8 =(0.84)^x`

`ln(y/0.8)=ln(0.84)^x`

`ln(y/0.8)=x ln(0.84)`

`(ln(y/0.8))/ln(0.84) =x`