Question

How do you solve `ln x^3 = 2 ln 5 - 3 ln 2`?

Answer 1

`x=root3(25/8)=root3 25 / 2`

Explanation:

`lnx^3-2ln5+3ln2=0`
`lnx^3-ln5^2+ln2^3=0`
`lnx^3-ln25+ln8=0`
`ln((8x^3)/25)=0`
`e^0=(8x^3)/25`

`1=(8x^3)/25`

`25=8x^3`

`25/8=x^3`

`x=root3(25/8)=root3 25 / 2`