Question

How do you factor `6t^4 + t^2 - 12`?

Answer 1

`(sqrt3*t+2)(sqrt3*t-2)(2t^2+3)`

Explanation:

`6t^4+t^2-12 =6t^4+9t^2-8t^2-12=3t^2(2t^2+3)-4(2t^2+3) =(3t^2-4)(2t^2+3)=(sqrt3*t+2)(sqrt3*t-2)(2t^2+3)`[Ans]