How do you solve #x^2 - 12x + 36 = 49#?
1 Answer
Apr 23, 2016
#x=-1#
#x=13#
Explanation:
Given -
#x^2-12x+36=49#
#x^2-12x+36-49=0#
#x^2-12x-13=0#
#x^2+x-13x-13=0#
#x(x+1)-13(x+1)=0#
#(x+1)(x-13)=0#
#x=-1#
#x=13#
